The area of a rectangle gets reduce by 80 sq. units, if its length is reduce by 5 units and the breadth is increased by 2 units. If we increase the length by 10 units and decrease the breadth by 5 units, the area increase by 50 sq. units. Find the area of the rectangle.
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Answered by
9
heya friend!!☺☺
here's your answer!!☺☺
Let x and y be the length and breadth of the rectangle.
Then, area of the triangle = xy
Now, from the given conditions we get
( x – 5)(y + 2) = xy – 80
2x – 5y = –70 ...(1)
( x + 10)(y – 5) = xy + 50
5x – 10y = –100 ...(2)
Simplifying (1) and (2), we get
x = 40
putting value of x in (1), we get
y = 30
hence the area of the rectangle,
xy=1200
hope it helps you!!☺☺
here's your answer!!☺☺
Let x and y be the length and breadth of the rectangle.
Then, area of the triangle = xy
Now, from the given conditions we get
( x – 5)(y + 2) = xy – 80
2x – 5y = –70 ...(1)
( x + 10)(y – 5) = xy + 50
5x – 10y = –100 ...(2)
Simplifying (1) and (2), we get
x = 40
putting value of x in (1), we get
y = 30
hence the area of the rectangle,
xy=1200
hope it helps you!!☺☺
Answered by
14
length = 40 units and breadth = 30 units
The area of a rectangle gets reduced by 80 sq units if its length is reduced by 5 units and breadth is increased by 2 units . if we increase the length by 10 units and decrease the breadth by 5 units the area increased by 50 sq units . Find the length and breadth of the rectangle
Let the length and breadth of rectangle be x and y respectively
•°• Area = xy
•°• (x - 5) (y + 2) = xy - 80
i.e, 2x - 5y + 70 = 0______( 1 )
and (x + 10) (y - 5) - xy = 50
==> 5x + 10y = 100
Divide both side by 5
==> x + 2y = 20
==> x - 2y +20 = 0________( 2 )
multiply ( 2 ) by 2 , we get
2x - 4y = -40______( 3 )
subtracting ( 3 ) from ( 1 ), we get
==> -y = -30
•°• 2x -5(30) = -70
==> 2x = -70 + 150
•°• Length = 40 units
and
Breadth = 30 units
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