The area of a rectangle gets reduced by 80 sq. units if its length is reduced by 5 units and the breadth in increased by 2 units. If we increase the length by 10 units and decrease the breadth by 5 units, the area in creased by 50 square units. Find the length and breadth of the rectangle.
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Answers
Let the length of the rectangle be x and breadth be y
Therefore Originally Area = xy sq units.
According to situation 1
Length = x - 5
Breadth = y + 2
New Area = (x - 5) (y +2) which is 80 sq units less than the original area
∴ (x - 5) (y + 2) = xy - 80
xy + 2x - 5y -10 = xy - 80
2x - 5y = - 70 -----( i )
According to situation 2
Length = x + 10
Breadth = y - 5
New Area = (x + 10) (y - 5) which is 50 sq units more than the original area
∴ (x + 10) (y - 5) = xy + 50
xy - 5x + 10y -50 = xy + 50
-5x + 10y = 100 ---( ii )
Multiplying eq (i) with 2 to make coefficient of y equal
4x - 10y = -140 ---- ( iii )
Adding eq (ii) and (iii)
-5x + 10 y + 4x - 10y = 100 - 140
- x = -40
x = 40
Putting value of x in eq (i)
2(40) - 5y = -70
80 - 5y = -70
-5y = -150
y = 30
∴ Length of the rectangle is 40 units and breadth is 30 units.
length = 40 units and breadth = 30 units
The area of a rectangle gets reduced by 80 sq units if its length is reduced by 5 units and breadth is increased by 2 units . if we increase the length by 10 units and decrease the breadth by 5 units the area increased by 50 sq units . Find the length and breadth of the rectangle
Let the length and breadth of rectangle be x and y respectively
•°• Area = xy
•°• (x - 5) (y + 2) = xy - 80
i.e, 2x - 5y + 70 = 0______( 1 )
and (x + 10) (y - 5) - xy = 50
==> 5x + 10y = 100
Divide both side by 5
==> x + 2y = 20
==> x - 2y +20 = 0________( 2 )
multiply ( 2 ) by 2 , we get
2x - 4y = -40______( 3 )
subtracting ( 3 ) from ( 1 ), we get
==> -y = -30
•°• 2x -5(30) = -70
==> 2x = -70 + 150
•°• Length = 40 units
and
Breadth = 30 units