The area of a rectangle is 120 cm2. The length of the rectangle is eight less than the twice of the width. Find the dimensions of the rectangle.
Answers
Answered by
2
Let , the width be x,
therefore, the length = 2x -8
Given, area of the rectangle = 120cm^2.
Now,
(2x -8 ) × x = 120
=> 2x^2 -8x = 120
=> 2x^2 -8x -120 = 0
=> 2x^2 +6x -15x -120 = 0
=> 2x(x + 3) - 15 ( x+ 6) = 0
Sorry , bhai , glti ho skti he ,.
Toh please, factorisation wala part , kr lena .
Middle term splitting method use krna .
Abhi dimaag kaam nhi kr rha he.
Sorry ...☝☝ waala wrong hua he , factorisation part , woh khud kr lena , phir x ka value aa jayega
therefore, the length = 2x -8
Given, area of the rectangle = 120cm^2.
Now,
(2x -8 ) × x = 120
=> 2x^2 -8x = 120
=> 2x^2 -8x -120 = 0
=> 2x^2 +6x -15x -120 = 0
=> 2x(x + 3) - 15 ( x+ 6) = 0
Sorry , bhai , glti ho skti he ,.
Toh please, factorisation wala part , kr lena .
Middle term splitting method use krna .
Abhi dimaag kaam nhi kr rha he.
Sorry ...☝☝ waala wrong hua he , factorisation part , woh khud kr lena , phir x ka value aa jayega
Similar questions