Question

the area of a rectangle is 168m².If the length is 14 m. find its breadth.Also ,find its perimeter​

Answer 1

Correct Question-:

• The area of a rectangle is 168m² . If the length is 14 m . Find its breadth and perimeter .

AnswEr-:

• $\underline{\boxed{\star{\sf{\purple{Breadth \:of \:Rectangle \:: \: 12 m }}}}}$
• $\underline{\boxed{\star{\sf{\purple{Perimeter \:of \:Rectangle \:: \: 52 m }}}}}$

Explanation-:

Given-:

• The area of a rectangle is 168m².
• The length of Rectangle is 14 m .

To Find-:

• The Perimeter and Breadth of Rectangle.

Now ,

• $\underline{\boxed{\star{\sf{\purple{Area \:of \:Rectangle \:: \: Length\times breadth}}}}}$

Here ,

• Length of Rectangle = 14 m
• Breadth of Rectangle = ??
• Area of Rectangle = 168 m².

Now ,

• 168m² = 14 × breadth
• 168/14 = Breadth
• Breadth = 12 m

Therefore,

• Breadth of Rectangle-: 12 m ...1

Now ,

• $\underline{\boxed{\star{\sf{\purple{Perimeter \:of \:Rectangle \:: \: 2(Length+ breadth)}}}}}$

Here ,

• Length of Rectangle = 14 m
• Breadth of Rectangle = 12 m ......[ From 1]

Now ,

• $\implies {\large{\sf{Perimeter _{Rectangle}= 2(14 +12)}}}$
• $\implies {\large{\sf{Perimeter _{Rectangle}= 2 \times 26 }}}$
• $\implies {\large{\sf{Perimeter _{Rectangle}= 52m}}}$

Therefore,

• $\underline{\boxed{\star{\sf{\purple{Perimeter \:of \:Rectangle \:: \: 52 m }}}}}$

Hence ,

• $\underline{\boxed{\star{\sf{\purple{Breadth \:of \:Rectangle \:: \: 12 m }}}}}$
• $\underline{\boxed{\star{\sf{\purple{Perimeter \:of \:Rectangle \:: \: 52 m }}}}}$

♡ Figure related to the answer -:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 14 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 12 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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Answer 2

${\underline{\underline{\bf{Given:}}}}$

• Area of a rectangle = 168 m².
• Length of the rectangle = 14 m.

${\underline{\underline{\bf{Need\:to\:find:}}}}$

• The breadth of the rectangle.
• Perimeter of the rectangle.

${\underline{\underline{\bf{Formulae\:to\:be\:used:}}}}$

$\underline{\boxed{\sf{{Area}_{(Rectangle)}=l\times b\:sq.units}}}$

$\underline{\boxed{\sf{{Perimeter}_{(Rectangle)}=2(l+b)\:units}}}$

$\sf{Here,}$

$\:\:\:\:\:\:\bullet{\sf{\:l=length}}$

$\:\:\:\:\:\:\bullet{\sf{\:b=breadth}}$

${\underline{\underline{\bf{Solution:}}}}$

Breadth of the rectangle:

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ As the area of rectangle is given, ‎it can be found by substituting the given measures i.e, the measures of length and the value of area in the formula that we use to find the area of rectangle.

$\:\:\:\:\:\:\:\:\implies{\sf{Area=Length\times Breadth}}$

$\:\:\:\:\:\:\:\:\implies{\sf{168=14\times Breadth}}$

$\:\:\:\:\:\:\:\:\implies{\sf{\frac{168}{14}=Breadth}}$

$\:\:\:\:\:\:\:\:\implies{\underline{\underline{\sf{\red{12\:m=Breadth}}}}}$

Perimeter of the rectangle:

Now, we have all the required measures to find the perimeter. So, let's find the perimeter using the formula:

$\:\:\:\:\:\:\:\:\implies{\sf{2\times(Length+Breadth)\: units}}$

$\:\:\:\:\:\:\:\:\implies{\sf{2\times (14+12)}}$

$\:\:\:\:\:\:\:\:\implies{\sf{2\times 26}}$

$\:\:\:\:\:\:\:\:\implies{\underline{\underline{\sf{\red{52\:metres}}}}}$

${\underline{\underline{\bf{Final\:answer:}}}}$

• The breadth of the rectangle is 12 m.
• The perimeter of the rectangle is 52 m.

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