Question

The area of a rectangle is 192 cm2 and its perimeter is 56 cm. Find the dimensions of rectangle.​

Answer 1

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Step-by-step explanation:

Answer

Correct option is

A

16

Let the length of the rectangle =l cm and breadth =b cm.

Area of the rectangle =l×b=192cm

2

....(1)

Perimeter of the rectangle =2(l+b)=56 cm

⇒l+b=28 or l=28−b ....(2)

Putting the value of l in equation (1), we get

(28−b)×b=192

28b−b

2

=192

b

2

−28b+192=0

(b−16)(b−12)=0

=>b=16 or 12 cm

Substituting the value of b =16 cm in equation (1), we get

l×16=192

⇒l=12 cm

Similarly, if b =12 cm, l=16 cm.

Dimension of the rectangle are 12 cm and 16 cm.