The area of a rectangle is 1936 sq.m. If the Length of the rectangle is 4 times its breadth, find the dimensions of the rectangle.
Answers
Answered by
50
Heya dear user !!!
Here is your answer,
================================
Given :-
The area of the rectangle is 1936 m square.
According to the question
The length of the rectangle is 4 times its breadth.
Let, the breadth be x m
So, length = 4x m
Area of the rectangle = length*breadth
=> 1936 = x*4x
=> 1936 = 4x²
=> 1936/4 = x²
=> 484 = x²
=> √484 = x
=> 22 = x
Hence, breadth of the rectangle = x = 22m
and length = 4x = 4*22 = 88 m
================================
Hence,
the dimensions of the rectangle are 22 m and 88 m.
================================
Hope it helps.
Here is your answer,
================================
Given :-
The area of the rectangle is 1936 m square.
According to the question
The length of the rectangle is 4 times its breadth.
Let, the breadth be x m
So, length = 4x m
Area of the rectangle = length*breadth
=> 1936 = x*4x
=> 1936 = 4x²
=> 1936/4 = x²
=> 484 = x²
=> √484 = x
=> 22 = x
Hence, breadth of the rectangle = x = 22m
and length = 4x = 4*22 = 88 m
================================
Hence,
the dimensions of the rectangle are 22 m and 88 m.
================================
Hope it helps.
Answered by
13
Answer:
Solution:- Given that the area of the rectangle is 1936²m.
And the length of the rectangle is 4 times it's breadth, it means that the breadth is x m and the length is 4x m.
So, Area of a rectangle= l × b
1936 m² = 4x m × xm
1936 m² = 4x²m
1936 / 4. = x²m
484 m²
So as we all know that the square of 22 is 484, so the breadth is 22m and the length is 4x = 4×22 = 88m
Hope it helps you
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