Question

The area of a rectangle is 45 15/16 cm ². If one edge is 6 1/4 cm, find the other.
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Answer 1

Given:- area of a rectangle is 45 15/16 cm² and one of edge is 6 1/4 cm.

To find:- Length of rectangle.

Solution :-

$\sf \: area \: of \: rectangle = 45 \dfrac{15}{16} \\ \\ \sf length \times breadth = \dfrac{735}{16} \\ \\ \sf length \times 6 \dfrac{1}{4} = \frac{735}{16} \\ \\ \sf length = \frac{735}{16} \div \frac{25}{4} \\ \\ \sf \: length = \frac{735}{16} \times \frac{4}{25} \\ \\ \sf \boxed{ \bf \: length = 7.35cm}$

Therefore, length of rectangle is 7.35cm.

Extra information about rectangle:-

• Area of rectangle = length × breadth

• Perimeter of rectangle = 2(l+b)

Answer 2

Step-by-step explanation:

n+n+1+n+2=36

⟶3n+3=36

⟶3n=33

⟶n=

3

33

⟶

n=11