Question

The area of a rectangle is 540 cm2 and its length is 36cm .find its width and perimeter.????!

Answer 1

Hello friend,
$area \: of \: rectangle = l \times b \\ {540cm}^{2} = 36cm \times b \\ \frac{540}{36} = b$
15 cm= breadth
Perimeter= 2(l+b)
= 2( 36+15)cm
= 2 × 51cm= 102cm
Hope it helps☺

Answer 2

✬ Width = 15 cm ✬

✬ Perimeter = 102 cm ✬

Step-by-step explanation:

Given:

• Area of rectangle is 540 cm².
• Length of rectangle is 36 cm.

To Find:

• What is the width and perimeter of the rectangle ?

Solution: Let the measure of width of rectangle be x cm. As we know that

★ Area of Rectangle = Length x Width ★

A/q

• Area = 540 cm²

$\implies{\rm }$ 540 = ( 36 x Width )

$\implies{\rm }$ 540/36 = Width

$\implies{\rm }$ 15 cm = Width

So, The measure of width of the given rectangle is 15 cm.

Now formula for perimeter of rectangle is

★ Perimeter = 2 ( Length + Width ) ★

$\implies{\rm }$ Perimeter = 2 ( 36 + 15 ) cm

$\implies{\rm }$ Perimeter = 2 $\times$ 51 cm

$\implies{\rm }$ Perimeter = 102 cm

Hence, The perimeter of the rectangle is 84 cm.

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➟ Opposite sides of a rectangle are equal.

➟ Each angle is of 90°.

➟ Diagonals of rectangle are equal to each other.