Question

The area of a rectangle is 540cm and its lenths is 36cm find its width and perimeter

Answer 1

Area = length *width
540= 36*width
width=540÷36
width=15 cm
Perimeter = 2× ( l+ b)
Perimeter = 2×( 36+ 15)
Perimeter= 102 cm

Answer 2

The width of a rectangle(b) = 15 cm and the perimeter of a rectangle = 102 cm

Step-by-step explanation:

Given,

The area of a rectangle = 540 $cm^2$ and

the length of a rectangle(l) = 36 cm

To find, the width of a rectangle(b) and perimeter = ?

We know that,

The area of a rectangle = l × b

⇒ 36 × b = 540

⇒ $b=\dfrac{540}{36}=15cm$

∴ The width of a rectangle(b) = 15 cm

The perimeter of a rectangle = 2(l + b)

= 2 × (36 cm+ 15 cm)

= 2 × 51 cm

= 102 cm

Hence, the width of a rectangle(b) = 15 cm and the perimeter of a rectangle = 102 cm