Question

The area of a rectangle is (6x2 -7x -5). If its breadth is (2x+1), then find its length.

Answer 1

Answer:

let length be l.

area of rectangle : l×b

6x^2-7x-5 = l × (2x+1)

6x^2-10x+3x-5 = l(2x+1)

2x(3x-5) + 1(3x-5) = l(2x+1)

(2x+1)(3x-5) = l(2x+1)

l = [(2x+1)(3x-5)]/(2x+1)

l = 3x-5

Answer 2

Are of rectangle=6x2-7x-5

breadth=2x+1

length=?

area of rectangle=length ×breadt

6

$6{x}^{2} - 7x - 5 = l \times 2x + 1 \\ 6 {x}^{2} - 7x - 5 = l2x + 1 \\ (3x - 5) (2x + 1) = l2x + 1 \\ l = (3x - 5)(2x + 1) \div 2x + 1 \\ l = 3x - 5$

lenght=3x-5

hope its helpful

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