Question

The area of a rectangle is 72 cm. The width is twice its length. What is the perimeter of the rectangle?

Answer 1

Answer:

Step-by-step explanation:

Area Of Triangle = l*b = 72 cm.

b = 2l.

l*b = l*2l = 72 cm.

2l² = 72 cm.

l² = 72/2 cm.

l² = 36 cm.

l = √36 cm.

l = 6 cm.

b = 2l

Therefore,b = 2(6) = 12 cm.

Perimeter Of Rectangle = 2(l+b) = 2(6+12) = 2(18) = 36 cm.

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Answer 2

❖ Perimeter : 36 cm

Given

Area of Rectangle : 72cm^2

Width = Double to length

To find

Perimeter of Rectangle : 2 ( l + b )

Calculation

Let's assume length = 'n' cm

∴ Width / Breadth = 2n

According to our assumption,

Area = l × b

= n × 2n = 2 n^2 cm^2

☆ According to question -

2 n^2 = 72

n^2 = 72 ÷ 2 = 36

n = √36 = 6

∴ n = 6 cm

As, n = length = 6cm

2n = width = 2 × n = 2 × 6 = 12cm

Solution

length = 6 cm

width = 12 cm

∴ Perimeter = 2 ( l + b )

= 2 ( 6 + 12 )

= 2 × 18

= 36 cm

Hope, your doubt was clarified

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