Question

The area of a rectangle is given by A = 6x²y + 4y²x and the width of rectangle is w= 2xy. What is the perimeter of rectangle ?​

Answer 1

Answer:

area of rectangle= Length×breadth

=L×B

here area,A= 6x²y+4y²x

and breadth = W= 2xy

let, length be L

then the required equation is:

$l \times 2xy = 6 {x}^{2}y + 4 {y}^{2}x \\ l = 6 {x}^{2}y + 4 {y}^{2}x \div 2xy \\ l = 3x + 4y$

hence, length of rectangle= 3x+4y

perimeter of rectangle= 2(L+B)

=2(3x+4y+2xy)

6x+8y+4xy