Question

The area of a rectangular field is 0.5 hectare. If one of the side of field is 40m, find the other side.

Answer 1

Answer:

Area of rectangular field=0.5ha

1ha=10000m^2

Now area=0.5×10000=5000m^2

Area of rectangle=l×b

5000=l×12.5m

l=5000/12.5

l=400m

other side=400m

Answer 2

$\bf \pink{Given}\begin{cases}&\sf{Area\:of\:the\:rectangular\:field=\bf{0.5\:hectare=5000\:m^2.}\sf{(\because\:1\:hectare=10000\:m^2)}} \\ \\ &\sf{Breadth\:of\:the\:rectangular\:field=\bf{40\:m.}}\end{cases}$

To FinD:-

The Length of the rectangular field.

Solution:-

• Let the length be l m.

We know that,

$\normalsize{\pink{\underline{\boxed{\bf{\:Area_{(rectangle)}=Length\times\:breadth}}}}}$

where,

• Length = l m
• Area = 5000 m²
• Breadth = 40 m

Putting the values,

$\normalsize\implies{\sf{5000=l\:\times40}}$

$\normalsize\implies{\sf{\dfrac{5000}{40}=l}}$

$\normalsize\implies{\sf{\dfrac{500\cancel{0}}{4\cancel{0}}=l}}$

$\normalsize\implies{\sf{\cancel{\dfrac{500}{4}}=l}}$

$\normalsize\implies{\sf{125=l}}$

$\normalsize\therefore\boxed{\mathfrak{\pink{Length=125\:m.}}}$

VerificatioN:-

$\normalsize\implies{\sf{Area_{(rectangle)}=Length\times\:breadth}}$

$\normalsize\implies{\sf{5000=125\times40}}$

$\normalsize\implies{\sf{5000=5000}}$

$\normalsize\therefore\boxed{\bf{LHS=RHS.}}$

• Hence verified.

The length of the rectangular field is 125 m.