Question

The area of a rectangular field is 162m2 and its length is twice its width. Find the dimensions of the field.

Answer 1

Question:-

The area of a rectangular field is 162m² and its length is twice its width. Find the dimensions of the field.

Answer:-

• The dimensions of field are 18 m and 9 m.

To find:-

• Length and breadth of field

Solution:-

• Length (l)= 2x m
• Breadth (b) = x m
• Area = 162 m²

$\blue{ \boxed{ \red{ \underline{ \underline{ \huge{ area = l \times b}}}}}}$

$\large{ : \implies \: 2x \times x = 162}$

$\large{ : \implies \: 2 {x}^{2} = 162}$

$\large{ : \implies \: {x}^{2} = \frac{162}{2} }$

$\large{ : \implies \: {x}^{2} = 81}$

$\large{ : \implies \: x = \sqrt{81} }$

$\large{ : \implies \: x = 9}$

• The value of x is 9.

___________________

• Length = 2x = 2×9 = 18 m
• Breadth = x = 9 m

___________________

Hence,

The dimensions of field are 18 m and 9 m.

Answer 2

Answer

• The length and the breadth are 18 m & 9 m

Explanation

Given

• Area of the rectangle = 162 m^2
• Length of the rectangle = Twice its breadth

To Find

• Dimensions of the field

Solution

Let the breadth of the rectangle be b

✭ Finding the area

→ Area = Length × Breadth

→ l×b = 162

[Length = 2x]

→ 2x × x = 162

→ 2x² = 162

→ x² = 162/2

→ x² = 81

→ x = √81

→ x = 9 m

✭ Breadth of the Rectangle

→ Breadth = x

→ Breadth = 9 m

✭ Breadth of the rectangle

→ Length = 2x

→ Length = 2×9

→ Length = 18 m