The area of a rectangular field is (x²-6x+5) m². If it's length is (x-1) m, find its width
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Given data :
➜ Area of rectangular field = {x² - 6x + 5} m²
➜ Length of rectangular field = {x - 1} m
Solution : Now, by formula of area of rectangle;
➜ Area of rectangular field = Length * Breadth
➜ x² - 6x + 5 = {x - 1} * Breadth
➜ x² - 5x - 1x + 5 = {x - 1} * Breadth
➜ x {x - 5} - 1 {x - 5} = {x - 1} * Breadth
➜ {x - 5} {x - 1} = {x - 1} * Breadth
After cancellation {x - 1}
➜ Breadth = {x - 5} m
Answer : Hence, the width of rectangular field is {x - 5} m.
{Verification :
➜ Area of rectangular field = Length * Breadth
➜ Area of rectangular field = {x - 1} * {x - 5}
➜ Area of rectangular field = x * {x - 1} - 5 * {x - 1}
➜ Area of rectangular field = x² - x - 5x + 5x
➜ Area of rectangular field = {x² - 6x + 5} m²
Hence it verified }
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