Math, asked by RBHGAMING, 4 days ago

The area of a rectangular field is (x²-6x+5) m². If it's length is (x-1) m, find its width​

Answers

Answered by nilesh102
2

Given data :

➜ Area of rectangular field = {x² - 6x + 5} m²

➜ Length of rectangular field = {x - 1} m

Solution : Now, by formula of area of rectangle;

➜ Area of rectangular field = Length * Breadth

➜ x² - 6x + 5 = {x - 1} * Breadth

➜ x² - 5x - 1x + 5 = {x - 1} * Breadth

➜ x {x - 5} - 1 {x - 5} = {x - 1} * Breadth

➜ {x - 5} {x - 1} = {x - 1} * Breadth

After cancellation {x - 1}

➜ Breadth = {x - 5} m

Answer : Hence, the width of rectangular field is {x - 5} m.

{Verification :

➜ Area of rectangular field = Length * Breadth

➜ Area of rectangular field = {x - 1} * {x - 5}

➜ Area of rectangular field = x * {x - 1} - 5 * {x - 1}

➜ Area of rectangular field = x² - x - 5x + 5x

➜ Area of rectangular field = {x² - 6x + 5} m²

Hence it verified }

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