The area of a rectangular field whose length is twice it's breadth is 2450 m square. Find the perimeter of the field
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7
Let the breadth be x meters
So, the length be 2x meters
According to Question,
Area of Rectangle = 2,450 m²
⇒ ( 2x × x ) = 2,450
⇒ 2x² = 2,450
⇒ x² = 2,450 / 2
⇒ x² = 1,225
⇒ x = √1,225
⇒ x = 35
Breadth = x = 35 m
Length = 2x = 2(35) = 70 m
Hence, length & breadth of the rectangle are 70 meters and 35 meters respectively.
∴ Perimeter of Rectangle
= 2( length + breadth )
= 2( 70 + 35 ) m
= 2 × 105 m
= 210 m
Hence, the perimeter of the rectangle is 210 meters.
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So, the length be 2x meters
According to Question,
Area of Rectangle = 2,450 m²
⇒ ( 2x × x ) = 2,450
⇒ 2x² = 2,450
⇒ x² = 2,450 / 2
⇒ x² = 1,225
⇒ x = √1,225
⇒ x = 35
Breadth = x = 35 m
Length = 2x = 2(35) = 70 m
Hence, length & breadth of the rectangle are 70 meters and 35 meters respectively.
∴ Perimeter of Rectangle
= 2( length + breadth )
= 2( 70 + 35 ) m
= 2 × 105 m
= 210 m
Hence, the perimeter of the rectangle is 210 meters.
✪ Be Brainly ✪
Answered by
6
Solution is in the pic
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