Math, asked by hgalsansvindurginn, 1 year ago

The area of a rectangular field whose length is twice its breadth is 2450 sq.m. Find the perimeter of the field

Answers

Answered by 7489
339
=B=2L
=Area=2450
 =L×B=2450
=L×2L=2450
= L square= 2450/2
 =L square= 1225
 =L=35m
 =B=70m
Perimeter = 2(L+B)
 =2(35+70)
 =210 m
Answered by amitnrw
407

Answer:

210 m

Step-by-step explanation:

The area of a rectangular field whose length is twice its breadth is 2450 sq.m. Find the perimeter of the field

Let say Breadth = B m

then Length = 2B m

Area =Length * Breadth

2B * B

2{b}^{2}  = 2450 \\  {b}^{2}  = 1225 \\  {b}^{2}  =  {35}^{2}  \\ b = 35

Breadth = 35 m

Length = 2 × 35 = 70 m

Perimeter = 2 × (Breadth + Length)

= 2 × (35 + 70)

= 2 × 105

= 210 m

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