Question

The area of a rectangular garden of length 40 m, is 1000 sqm. Find the breadth of the garden and its perimeter. The garden is to be enclosed by 3 rounds of fencing, leaving an entrance of 4 m. Find the cost of fencing the garden at a rate of 250 rupees per metre.​

Answer 1

Answer:

Heyaa♡♡

$area = l \times b \\ l \times b = 1000m {}^{2} \\ 40 \times b = 1000 \\ b = \frac{1000}{40} \\ b = 25m {}^{2}$

$perimeter = 2(l + b) \\ = > 2(40 + 25) \\ = > 2(65) \\ = > 130m$

$entrance = 4m \\ so \: 130m - 4m \\ = > 126m \\ Fencing \: 3 \: rounds \: so \\ = > 3 \times perimeter \\ = > 3 \times 126 \\ = > 378m \\ given \: cost \: of \: fencing \: 250 \: rs \: per \: meter \\ = > 378 \times 250 \\ = > 94500 \: rupees$

Hope it helped you.