Question

The area of a rectangular mirror is 11 11/16 square feet. The width of the mirror is 2 3/4 feet. If there is a 5 foot tall space on the wall to hang the mirror, will it fit? Explain.

Answer 1

$area = 11 \frac{11}{16} = \frac{187}{16} \: sq \: feet \\ width = 2 \frac{3}{4} = \frac{11}{4} feet \\ length = \frac{area}{width} \\ length = \frac{ \frac{187}{16} }{ \frac{11}{4} } = \frac{187}{16} \times \frac{4}{11} \\ length = \frac{17}{4} = 4 \frac{1}{4} \: feet \\ the \: space \: to \: hang \: is \: 5 \: feet > 4 \frac{1}{4} feet \: ie \: the \: length \: of \: the \: mirror \\ so \: it \: can \: be \: hanged$

Answer 2

Answer:

area = 11 \frac{11}{16} =  \frac{187}{16}  \:  sq \: feet \\ width = 2 \frac{3}{4} =  \frac{11}{4}  feet \\ length =  \frac{area}{width}  \\ length =  \frac{ \frac{187}{16} }{ \frac{11}{4} }  =  \frac{187}{16}  \times  \frac{4}{11}  \\  length =  \frac{17}{4}  = 4 \frac{1}{4}   \: feet \\ the \: space \: to \: hang \: is \: 5 \: feet > 4 \frac{1}{4} feet \: ie \: the \: length \: of \: the \: mirror \\ so \: it \: can \: be \: hanged