Question

the area of a rectangular Park is 4100 m square and its breadth is 50 M find the cost of fencing it @ rupees 30 per metre

Answer 1

hiii!!!

here's ur answer...

given the breadth of the rectangular park is 50m.

area of the rectangular park = 4100m²

therefore l × b = 4100m²

=> l × 50 = 4100m²

=> l = 4100/50

=> l = 82m

VERIFICATION:-

area of the rectangular park = l × b

= 82 × 50

= 4100m²

hence verified

thus the Length of the rectangular park is 82m.

now, we have to find the perimeter to find the cost of fencing.

perimeter of the rectangular park = 2 ( l + b )

= 2 ( 82 + 50 )

= 2 × 132

= 264m

total cost of fencing at the rate of ₹30 per m = 264 × 30 = ₹7920

hope this helps u..!!

Answer 2

Heya ☺

Given that

Area of a rectangle = 4,100 m^2

Breadth = 50 m

Fencing = ₹30 per metre

Solution

Let the length of a rectangle be (x) m. Then,

Area of a rectangle = Length × Breadth

=> 4,100 = x × 50

=> 4,100 = 50x

=> x = 4,100/50

=> x = 82

Hence , the length of a rectangle is 82 m.

Perimeter of a rectangle = 2(l+b)

= 2(82+50)

= 2(132)

= 264 m


Cost of fencing = ₹(264 × 30)

= ₹7,920

Thanks