The area of a rectangular playground is 4800m^2. Find the cost of covering it with gravel 1 cm deep,If the gravel costs ₹260 per cubic metre.
please give the answer with steps.
Answers
Answered by
108
1 cm = 0.01m
total cubic meter to fill with gravel = 0.01*4800
= 48
therefore total cost = 48*260
=12480 rs
total cubic meter to fill with gravel = 0.01*4800
= 48
therefore total cost = 48*260
=12480 rs
Answered by
78
1 cm =0.01m
volume=L*B*H (L*B=4800m^2)
volume =4800*0.01
volume =48m^3
1m^3=260 Rs
so for 48m^3=48*260 =12480 Rs
volume=L*B*H (L*B=4800m^2)
volume =4800*0.01
volume =48m^3
1m^3=260 Rs
so for 48m^3=48*260 =12480 Rs
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