Question

The area of a rectangular pool is 1260 ft2. Find the dimensions of the rectangle if one side of the pool is 48ft more than three time the other side

Answer 1

Answer:

$\tt -30\: ft \: and \: 14\: ft$

Step-by-step explanation:

$\sf \large \red{ Given:-}$

$\tt Area = 1260 \: ft^2$

$\tt One \:side =x$

$\tt Other \:side =48+3x$

$\sf \large \red{Solution:-}$

We know that,

$\boxed{\rm Area_{Rectangle}= l×b}$

$\tt 1260 = x(48+3x)$

$\tt 1260 = 48x+3x^2$

$\tt 3x^2+48x-1260=0$

$\tt 3(x^2+16x-420)=0$

$\tt x^2+16x-420=0$

$\tt x^2+30x-14x-420=0$

$\tt x(x+30)-14(x+30)=0$

$\tt (x+30)(x-14)=0$

$\tt x= -30\: or \: 14$