The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0
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y(y-5)=750 mark me briliant pls
according to question
let length= y m
width = y-5 m
area = 750
area of rec = l×b
750 = y (y-5)
750 = y^2 -5y
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