Question

The area of a regular hexagon is 50 in.2 Find the length of a side. Round your answer to the nearest tenth. (hint: Regular Hexagon contain 6 equilateral triangles, there is a formula for equilateral triangle)

a
4.4 in.
b
19.2 in.
c
7.6 in.
d
5.8 in.

Answer 1

Answer:

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Answer 2

Given :- The area of a regular hexagon is 50 in² .

To Find :- The length of a side in nearest tenth .

a) 4.4 in.

b) 19.2 in.

c) 7.6 in.

d) 5.8 in.

Solution :-

Let us assume that, length of a side of a regular hexagon is a in .

since regular hexagon contains 6 equilateral triangles .

so,

→ Area of regular hexagon = 6 * Area of an equilateral triangle with sides as a in.

then,

→ 6 * (√3/4 a²) = 50

→ 3√3 a² = 50 * 2

→ 3 * 1.73 a² = 100

→ 5.19 a² = 100

→ a² = (100 / 5.19)

→ a = 10/√(5.19)

→ a = 10 / 2.27

→ a = 4.4 in . (a) (Ans.)

Learn more :-

यदि किसी ठोस घन की प्रत्येक भुजा में 150% की वृद्धि

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