Question

The area of a regular hexagon is _______ times the area of an equilateral triangle with the same side length as that of the hexagon.

Answer 1

The area of a regular hexagon is 6 times the area of an equilateral triangle with the same side length as that of the hexagon

Explanation:

Let s be the side of hexagon and equilateral  triangle.

Area of a regular hexagon = $\dfrac{3\sqrt{3}}{2}s^2$

Area of equilateral triangle=$\dfrac{\sqrt{3}}{4}s^2$

Now Consider  , $\dfrac{\text{Area of hexagon }}{\text{Area of equilateral triangle}}$

$=\dfrac{\dfrac{3\sqrt{3}}{2}s^2}{\dfrac{\sqrt{3}}{4}s^2}=\dfrac{\dfrac{3}{1}}{\dfrac{1}{2}}=3\timess2=6$

Hence, the area of a regular hexagon is 6 times the area of an equilateral triangle with the same side length as that of the hexagon.

# Learn more :

ABCDEF is a regular hexagon with side is 6cm. find the area of regular hexagon

https://brainly.in/question/8010256

Answer 2

Answer:

6 times

Step-by-step explanation:

Just go for it