Question

the area of a regular hexagon of side 2√3 cm is

Answer 1

A hexagon can be thought of 6 equilateral triangles joined together of side 2√3 cm each

(If you don't observe that, then just join all the opposite vertices (diagonals) and see:) )

Area, A of an equilateral triangle is
$\frac{ \sqrt{3} {a}^{2} }{4}$

Here, a= 2√3 cm

So, A= 3√3 cm²

:. Area of the hexagon = 6A
$= 6 \times 3 \sqrt{3} \\ = 18 \sqrt{3} \: \: \: {cm}^{2}$

Hope this helps!!!
☺️☺️