Question

the area of a rhombus having the
two diagonals 2.2 m and 5,5 m is
m^2​

Answer 1

Answer:

area of rhombus =1/2×d1×d2

1/2×2.2×25

1.1×25

27.5 ans

Answer 2

Step-by-step explanation:

Question :-

• Find the area of a rhombus having two diagonals of measure 2.2 m and 5.5 m respectively.

To Find :-

• Area of rhombus.

Solution :-

Given : A rhombus having two diagonals of measure 2.2 m and 5.5 m respectively.

By using the formula,

${\sf{\longrightarrow Area\ of\ rhombus\ =\ \dfrac{1}{2} \times d_1 \times d_2}}$

Where,

• ${\sf{d_1}}$ = length of diagonal 1
• ${\sf{d_2}}$ = length of diagonal 2

According to the question, by using the formula, we get :

${\sf{\longrightarrow Area\ of\ rhombus\ =\ \dfrac{1}{2} \times d_1 \times d_2}}$

${\sf{\longrightarrow \dfrac{1}{2} \times 2.2 \times 5.5}}$

${\sf{\longrightarrow \dfrac{12.1}{2}}}$

${\sf{\longrightarrow 6.05\ m^2}}$

$\therefore$ Hence, area of rhombus is 6.05 m².

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$