the area of a rhombus is 36 CM square and one of its diagonal is 18 cm what its perimeter is
Answers
I suppose the question mean that the area is 36 sq. cm. The perimeter of the rhombus is 4 x sqrt 85.
A square of 6cm has an area of 36 sq cm. It’s diagonal is 6 x sqrt 2 or about 8.48 which is much shorter than 18. Hence the rhombus has to be distorted. 18 cm is the longer diagonal. For a rhombus, their diagonals cut perpendicularly and therefore can be considered to be made up of 4 equal right-angle triangles with two sides equal to half of the diagonals. Hence the total area of the rhombus is the product of the diagonals divided by 2. Hence the shorter diagonal is 36x2/18 = 4. Hence each side of the rhombus is sqrt of Sum of squares of half of diagonals = sqrt (9^2+2^2) = sqrt 85. Therefore the perimeter of the rhombus is 4 x sqrt 85.
Answer:
Firstly let d2 is x.
Area of rhombus =1/2*d1 *d2
36=1/2*18*x
36=9x
Tarnsposing 9
X=36/9
X=4cm
Perimeter =d1+d2
=(18+4)cm
=22cm
Step-by-step explanation: