Question

the area of a rhombus is 36 CM square and one of its diagonal is 18 cm its perimeter is​

Answer 1

Heya mate here is your answer:-
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●First of all we know that AREA OF A RHOMBUS= 1/2 × PRODUCT OF DIAGONALS.

●So, 1/2 × 18 × a = 36, where a is the other diagonal.
=>a=4.

●Now, Perimeter will be side ×4 as sides of rhombus are equal, so we will find the dide length now.

●Appyling pythagoras theorem,
$\sqrt{ {9}^{2} + {2}^{2} }$
$\sqrt{85}$
●So, the perimeter is :-

$4 \sqrt{85}$
Hope this helps