Question

The area of a rhombus is 96cm square. If one of its diagonals are 16 cm, then find the length of its sides ?

Answer 1

Hello Mate!

Let construct a rhombus with diagonal of 16 cm and d2

Area = 1/2 × d1 × d2

96 cm^2 = 1/2 × 16 cm × d2

96 cm^2 = 8 cm × d2

96 cm^2 / 8 cm = d2

12 cm = d2

Now half the diagonals to make a small triangle AOB

16/2 = 8 cm
12/2 = 6 cm

${h}^{2} = {b}^{2} + {p}^{2} \\ {h}^{2} = {8}^{2} + {6}^{2} \\ {h}^{2} = 64 + 36 \\ {h}^{2} = 100 \: {cm}^{2} \\ h = \sqrt{100} \\ h = 10 \: cm$

Hence side are length of 10 cm

Answer 2

Answer:

Step-by-step explanation:Hello Mate!

Let construct a rhombus with diagonal of 16 cm and d2

Area = 1/2 × d1 × d2

96 cm^2 = 1/2 × 16 cm × d2

96 cm^2 = 8 cm × d2

96 cm^2 / 8 cm = d2

12 cm = d2

Now half the diagonals to make a small triangle AOB

16/2 = 8 cm

12/2 = 6 cm

Hence side are length of 10 cm