Question

The area of a rhombus whose diagonal are of lengths 10cm and 8.2cm is
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Answer 1

Answer:

Area of the rhombus =1/2×d1d2 [where d1,d2 are

lengths of diagonals=1/2×10×8.2 cm2

=41 cm2

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Answer 2

SOLUTION:

It is given that diagonals of rhombus are 10cm and 8.2cm.

As we know that formula to find area of rhombus is:-

★½×Length of diagonal 1×Diagonal2

$\sf : \implies \: \: \frac{1}{2} \times 10cm \times 8.2cm$

$\sf : \implies \: \: \frac{1}{ \cancel2} \times { 10cm} \times \cancel{8.2cm}$

$\sf : \implies \: \: { 10cm} \times {4.1cm}$

$\sf : \implies \: \: {41cm}^{2}$

Hence area of rhombus is 41cm²

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MORE FORMULAE TO KNOW!

• Area of rectangle=length×breadth
• Area of square=Side²
• Area of ∆=½×Base×height
• Area of circle=πr²