the area of a right angle triangle is 24 cm square if one of the sides containing the right angle is 8 cm find the length of its hypotenuse
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Answered by
43
area of right triangle =1/2 *base*height
let the base be 8 cm
area of triangle=24 cm square
24=1/2 *8* height
24*2/4= height
48/4= height
6 cm=height
using phythagorus theorm
H^2=b^2 +p^2
hypotenuse = 8^2 + 6^2
h^2= 64 +36
h^2= 100
h= 10cm
let the base be 8 cm
area of triangle=24 cm square
24=1/2 *8* height
24*2/4= height
48/4= height
6 cm=height
using phythagorus theorm
H^2=b^2 +p^2
hypotenuse = 8^2 + 6^2
h^2= 64 +36
h^2= 100
h= 10cm
Answered by
27
Area of triangle =1/2×b×h
=>1/2×b×8=24
=>b=6cm
By Pythagoras theorem...
AB sq+BC sq=AC sq
8×8+6×6=AC sq
64+36= AC sq
√100= AC
AC =10 cm..
Hypotenuse is 10cm
Thank You!
=>1/2×b×8=24
=>b=6cm
By Pythagoras theorem...
AB sq+BC sq=AC sq
8×8+6×6=AC sq
64+36= AC sq
√100= AC
AC =10 cm..
Hypotenuse is 10cm
Thank You!
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