Question

the area of a right angle triangle is 30sq.m. its length is 80cm. then find its breadth. ​

Answer 1

${ \underline{ \huge{ \bf {AnsWer : }}}}$

We know that,

Area of a ∆ = ½ × base × height

=> 30 = ½ × 80 × height

=> 30 = 0.40 × height

=> 30/0.40 = height

=> height = 75cm.

Note :

➔ height = breadth

➔ length = base

Answer 2

${\boxed{\sf{Corrected\:question}}}$

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎The area of a right-angled triangle is 30 sq.m. If its perpendicular's length is 80 cm, then find its base length.

__________________________________________

${\boxed{\sf{Step\:by\:step\: explanation}}}$

${\underline{\underline{\bf{Given:}}}}$

• Area of a right-angled triangle = 30 m² (3,000 cm²).
• The length of its perpendicular = 80 cm.

${\underline{\underline{\bf{Need\:to\: find:}}}}$

• The length of its base.

${\underline{\underline{\bf{Formula\:to\:be\:used:}}}}$

$\underline{\boxed{\sf{{Area}_{[Right\:angled\: triangle]}=\frac{1}{2}\times Base\times Perpendicular\:sq.units}}}$

${\underline{\underline{\bf{Solution:}}}}$

As the measures of area and length of perpendicular is given, the base length of the right-angled triangle can be found by putting the given values in the formula of area of right-angled triangle and solve for 'base'.

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎$\underline{\sf{Area=\frac{1}{2}\times Base\times Perpendicular\:sq.units}}$

Now, insert the values in its respective places.

$\implies{\sf{3000=\frac{1}{\cancel{2}}\times Base\times \cancel{80}}}$

$\implies{\sf{3000=Base\times 40}}$

$\implies{\sf{\frac{300\cancel{0}}{4\cancel{0}}=Base}}$

$\implies{\sf{\frac{300}{4}=Base}}$

$\implies{\sf{\red{\underline{\underline{75\:cm=Base}}}}}$

${\underline{\underline{\bf{Required\:answer:}}}}$

• The base of the right-angled triangle is 75 cm.

____________________________________________