Question

The area of a right angle whose base is 4 centimetre is 8 cm square find the other two side of the right triangle.​

Answer 1

Answer:

base=4

area=8

b*h*1/2=8

8*h*1/2=8

4*h=8

h=8/4

h=2

therefore perpendicular=2

now,

by p.g.t

p2+b2=h2

2*2+4*4=h2

4+16=h2

20=h2

4.47=h

hope it helped

Answer 2

Answer:

Other two sides are 4 cm and 4$\sqrt{2}$ cm

Step-by-step explanation:

Area of the right angled triangle $8 cm^2$

base b = 4cm

Height or one of the sides of the triangle is

$A =\frac{1}{2} bh\\8= \frac{1}{2} \times 4 \times h \\h=4 cm$

One of the side is 4 cm

Remaining side  (hypotenuse =x)can be calculated by Pythagoras theorem

$hypotenuse ^2 =base^2 +hieght^2\\x^2 =4^2+4^2\\x^2 =32\\x=4\sqrt{2} cm$

Other two sides are 4 cm and 4$\sqrt{2}$ cm