Question

The area of a right-angled tiangle is 60 cm square and its smallest side is 8cm. what is its hypotenuse?

Answer 1

Let side 8cm be base of triangle.
Area of triangle is 1/2×b×h
60=1/2×8×h
h=15cm or p= 15cm

Pythagoras theorem
H^2 = b^2+p^2
H^2= 64+225
H^2=289
H=√289
H=17cm

Answer 2

IF WE TAKE THE BASE=8 CM SIDE AND LDT THE HIGHT =h so the area of the traingle=1/2.h.b from the question we get 1/2.h.b=60 or.1/2.h.8=60 or,h=15 in the rule of pythagores H^2= h^2+b^2=15^2+8^2=225+64=289 so, H^2=289 or, H=root289=17