Question

The area of a right-angled triangle is 20 cm ² and one of the sides containing the right triangle is 4 cm. Then the altitude on the hypotenuse is Please Provide correct labbeled figure very important without figure will be reported.

Answer 1

Given :

• Let the given triangle be ABC...
• One of the sides containing the right angle is 4 cm.. So let BC = 4 cm...

To Find : Height

Solution :

Area of a triangle is given by

$\frac{1}{2} \times base \times height$

With BC as base and AB as height....

By Substituting the values, we get,

$\frac{1}{2} \times 4 \times h = 20 \: {cm}^{2} \\ \\ = > h = \frac{20}{2} = 10 \: cm$

Therefore, height is 10 cm...

For the labelled diagram.... Refer to the attachment...

Mark as Brainliest....

Answer 2

• Area of any triangle = 1/2 * one side * corresponding altitude

• => 20 = 1/2 * 4 * a

• => a = 20/2 = 10cm

• So, now, sides of right triangle = 4cm & 10cm

• => hypotenuse = √(4² + 10²) = √116 = 2√29 cm

Now, again area of this right triangle = 1/2 * hypotenuse * corresponding altitude

• => 20 = 1/2 * 2√29 * h

• => h = 20/√29 = 20√29/29 cm = (20 * 5.38)/29 = 3.71 cm ( approx)

$hope \: its \: help \: u$