Question

The area of a right angled triangle is 60 m² and its smallest side is 8 cm. What is its hypotenuse

Answer 1

Area of right angled triangle = [ product of small sides] /2

Here,

60 = (8 × other side) /2

120 = 8 × other side

120/8 = other side

15 = other side

================

Hypotenuse² = 15² + 8²

Hypotenuse² = 225 + 64

Hypotenuse² = 289

Hypotenuse = 17 m



I hope this will help you


(-:

Answer 2

Heya !!!



Let the other side be X m


Smallest side of right angled triangle = 8 cm




Area of triangle = 60 m².


1/2 × Smallest side × Other side = 60 m




1/2 × 8 × X = 60 m





4X = 60


X = 60/4



X = 15 m




Other side = X = 15 m



By pythagoras theroem,




( Hypotenuse)² = ( Smallest Side)² + (Other side)²



(H)² = (8)² + (15)²


(H)² = 64 + 225



(H)² = 289



H = ✓289 = 17 m.




HOPE IT WILL HELP YOU....... :-)