The area of a right angled triangle is 600sqcm if the base of the tri exceeds the altitude by 10cm find dimensions of tri
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Answer:
Step-by-step explanation:
→ let the altitude of the triangle =x cm
→ base = (x+10) cm
→ area = 600 sq cm
→ 1/2× base×altitude = 600
→ x(x+10)= 2*600
→ x²+10x -1200=0
→ x² +40x-30x-1200=0
→ x(x+40)-30(x+40)=0
→ (x+40)(x-30)=0
→ x+40=0 or x-30=0
→ x= -40 or x= 30
→ x should be negative
→ x=30
→ base = x+10 =30+10=40
→ by Pythagoras theorem
→ hypotenuse square = base square+ altitude square
= (40)² + (30)²
=1600+900
=2500
→ hypotenuse =50
→ three sides of a triangle
→ 30cm,40cm and 50cm.
niral:
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