Question

The area of a right-angled triangle with a base of 7 cm and a height of 8 cm is

Answer 1

Answer:

=> The area is 28cm².

Step-by-step explanation:

Given that:-

In a triangle,

Base = $7$ inches

Height = $8$ inches

To find:- Area of an acute triangle = ?

For calculating the area,

We have to use the formula:

Area = $(\frac{1}{2} )\times b\times h$ square units

Plug all the given values, we get

=> Area = $(\frac{1}{2} )\times (7)\times (8)$

=> Area = $(\frac{1}{2} )\times (56)$

=> Area = $(\frac{56}{2} )$

=> Area = 28cm².

Hence, the required solution is 28cm².

Answer 2

As per the given data in the question

In the above question given that

We have find the value of given expression

Given the area of a right angled triangle base of $7 cm$ and height of $8 cm$

The base  of right angle triangle is $7 cm$

The height of right angle triangle is $8cm$

The right angle triangle formula Area $= \frac{1}{2} *b*h$

$\Rightarrow \frac{1}{2} *7*8\\\Rightarrow \frac{1}{2} *56\\\Rightarrow \frac{56}{2} \\\Rightarrow= 28cm^{2}$

Area $= 28 cm^{2}$

Hence the required value of Area is $=28 cm^{2}$.