The area of a right triangle is 'S' sq cm and one of the sides containing the right angle is 1 cm.The altitude on the hypotenuse is:
(a)25/t cm
(b)(S2 - t2) cm
(c)√ [t2 + (4S2)/t2] cm
(d)2St √ [t4 + (4S2)/t] cm
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Answer:
i think its option b
Step-by-step explanation:
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