Question

The area of a sector of a circle with radius 6 cm with angle of the sector is [60] ^0 is

Answer 1

Gɪᴠᴇɴ :-

• Radius (r) = 6 cm

• Angle (Φ) = 60°

ᴛᴏ ғɪɴᴅ :-

• Area of Sector

sᴏʟᴜᴛɪᴏɴ :-

We know that,

➡ Area of Sector = πr²Φ/360°

So,

=> πr²Φ/360

$\implies \: \frac{ \frac{22}{7} \times 6 \times 6 \times 60 }{360} \\ \\ \\ \implies \: \frac{ \frac{22}{7} \times 2160}{360} \\ \\ \\ \implies \: \frac{ \frac{47520}{7} }{360} \\ \\ \\ \implies \: \frac{47520}{7} \times \frac{1}{360} \\ \\ \\ \implies \: \frac{132}{7} \\ \\ \\ \implies \: 18.85$

Hence,

• Area of Sector = 18.85 ≈ 18.9 cm²

Answer 2

Answer:

Hi friend here is your answer...

We know that formula is theta/360*pier^2

Step-by-step explanation:

Hope my answer will help you..