Math, asked by ItzMayurBhai01, 3 months ago

The area of a sector of angle θ of a circle with R is

2πRθ/180

2πRθ/360

πR²θ/180

πR²θ/360​

Answers

Answered by Anonymous
10

Answer:

πR²θ/360

Step-by-step explanation:

AOBisasectorofradius=randthecentralangle=θ.

Tofindout−

theperimeterofthesectorAOB=?

Solution−

ThearclengthAB= 360 o

θ ×2×π×r= 360 o

πθ ×2r.

Nowtheperimeterofthesector=OA+OB+arcAB=r+r+360o

θ ×2πr=2r( 360° πθ+1).

Ans−Option A

hope it helps uh !!

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Answered by kunjika158
5

πR²θ/360 (D)

Explanation:

In a circle with radius r and centre at O, let ∠POQ = θ (in degrees) be the angle of the sector. Then, the area of a sector of circle formula is calculated using the unitary method.

For the given angle the area of a sector is represented by:

The angle of the sector is 360°, area of the sector, i.e. the Whole circle = πr2

When the Angle is 1°, area of sector = πr2/360°

So, when the angle is θ, area of sector, OPAQ, is defined as;

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