Question

The area of a square ABC is 49 cm Sq Find the area of the square obtained by joining the midpoint s of the sides of the square vkABCD​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

area of abcd =49cm²

construct a line pq joining the midpoints mo

let the midpoints mnop respectively

then, triangle pmq and reactangle abpq stands on same base between same parallel lines that's why

area (pmq) =½area (abpq) .......... equation 1

similarly area (opq) =½area (qpcd) ............equation 2

add equation 1 and equation 2

area (pmq +opq) =½area(abpq+qpcd)

area (mnop) =½area (abcd)

area (mnop) =49/2

area mnop =24.5cm²