Question

The area of a square field is 1125 sq. meters. If each of its sides in increased by 1 meter, what will be the increase in its area?

Answer 1

HELLO BUDDY .... !!

HERE IS YOUR ANSWER :
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Area of the square field =
$1125 \: m { }^{2}$


Let the side be x. Then ,

$x {}^{2} = 1125$


$x = \sqrt{1125}$


$x = 33.5 \: ( \: approx \: )$


CASE 1 : IF EACH SIDE INCREASED BY 1 M.

( EACH SIDE WILL BE OF 34.5 )

Then , the area will be :

$34.5 {}^{2} = 1190.5 \: m {}^{2}$
AREA OF 2nd SQUARE -
AREA OF 1st SQUARE = INCREASE IN AREA

1190.5 - 1125 = 65.5

Hence , the area increased is
$65.5 \: m {}^{2}$
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HOPE IT HELPS YOU...!!
THANKS !!

Answer 2

Answer:

Given

Side of the square field =16 m

Hence, area of square field can be calculated as follows:

Area =(side)

2

=(16 m)

2

=16 m×16 m

We get,

=256 m

2

Given

Each sides of its length is doubled

Hence, the new side will be =16 m×2

=32 m

The area of square can be calculated as follows:

Area =(side)

2

Area =(32)

2

=32 m×32 m

We get,

=1024 m

2

Thus, the increase in area of the square field will be =1024 m

2

−256 m

2

=768 m

2

Therefore, the increase in the area of the square field =768 m

2