Question

the area of a square field is 5184 find the area of rectangular field whose perimeter is equal to the perimeter of square field and whose length is twice of its breath

Answer 1

let 'l' be length and  'b'  be breath

let side of square be a

then area of square = a*a

               a=72

perimeter of square=4a

                                   =4(72)

                                       =288=perimeter of rectangle

              as per condition  2b=l

                                            b=l/2

perimeter of rectangle =2(l+b)

                                        288 =2(l+l/2)

                                         288=2l+l

                                       288/3=l

                                       l=96

b=l/2=96/2=48

area of rectangle =l*b=96*48=4608

                               

Answer 2

Here is your solution

Given :-

Area of square = 6889 m^2

we have to find perimeter of square =?

Now

Area of square = side^2

=>5184 m^2 = side^2

=>72m =side of square

Now

perimeter of square => 4× side .
=> 4×72=288m

Now,

Let,
The breadth of rectangle be x

Then the length be 2x

As we know that,

 perimeter of a rectangle =2(length+breadth)

And, perimeter of square = perimeter of rectangle = 288m 

288 = 2(x + 2x)

288/2 = 3x

144 = 3x

144/3 =x

48 = x

Then,

breadth of rectangle = x = 48 m 

and length of rectangle = 2x = (2×48) = 96m 

Now,

Area of rectangle = length×breadth

Here,

Area of rectangle =  48×96 

Area of rectangle =4608 m^2

Hopeit helps you