The area of a square field is 5184 m2. Find the area ofa rectangular field, we is equal to the perimeter of the square field and whose length is twice of its breadth ?
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Step-by-step explanation:
length of the square is √5184m
=72m
perimeter of the square is 4.72 m=288m
perimeter of the rectangle =288m
if length is 2xm,breadth is x m then
2(2x+x)=288
6x=288
x=48
area of the rectangular field is 96×48sq m
=4608sq m
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Answer:
side of square=✓5184=72cm
hence perimeter of square is 4×side=4×72=288cm
it is given that, length is twice of its breadth
let breadth bex,then length is 2x
perimeter of rectangle is x+2x+x+2x=288(ar.of square=ar.of rectangle)
6x=288
x=48
hence, length of rectangle is 96cm and length is 48
now,area of rectangle is l×b=96×48=4608sq.cm
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