Question

The area of a square field is 5184 metre square. Find the area of a rectangular field, whose perimeter is equals to the perimeter of the square field and whose length is twice of its breadth.​

Answer 1

Step-by-step explanation:

area of square field= s*s=5184

s^2=5184

s=√5184

s=72

perimeter. of square field=4*side

cm

=4*72=288cm

let breadth of rectangular field=x

length =2xcm

perimeter =2(l+b)

=2(3x)

=6xcm

ATQ. 6x=288

X=288/6=48cm

SO,

1. breadth of rectangular field=x=48cm
2. length of rectangular field=2x=2*48=96cm

AREA of rectangular field=L*B=96*48=4608cm^2

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Answer 2

Area of square = (side)²

We have area of square = 5184 m²

=> 5184 = (side)²

=> √5184 = side

=> side = 72 m

Now,

Perimeter of square = 4 × side

From above calculations we have side = 72 m

So,

=> 4 × 72

=> 288 m

Let breadth of rectangle be "M".

As said in question length is twice the breadth. So,

Length of rectangle = 2M.

Perimeter of rectangle = 2(length + breadth)

Also, said that

Perimeter of rectangle = Perimeter of square.

Means, Perimeter of rectangle = 288 m

=> 288 = 2(2M + M)

=> 288 = 2(3M)

=> 288 = 6M

=> M = 48

Then,

• Breadth = M = 48 m
• Length = 2M = 2(48) = 96 m

And

• Area of rectangle = length × breadth

=> 48 × 96

=> 4608 m².

∴ Length of rectangle is 96 m, Breadth is 48 m and Area of rectangle is 4608 m².