the area of a square is 49 square centimetre rectangle has the same perimeter of the square if the length of the rectangle is 9.3 cm what is its breadth also find which has greater area
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Let area of square be x^2
and here x^2=49
x=+-7
since length can't be negative so a=7
and we know that
perimeter of rectangle = perimeter as square(.given)
length of rectangle =9.3(given)
perimeter of square =4x (where x is the length of side)
plugging in the values
and perimeter of rectangle=2(l+b) where l is length and b is breadth
we get
4x = 2( l + b )
plugging in the given values we get
4*7=2(9.3+b)
28=18.6+2b
28-18.6=2b
9.4/2=b
b=4.7
area=l*b
=4.7*9.3
4.7 * 9.3 = 43.71
hence 49>43.71
so square has more area
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