the length of the tangent drawn from an external point P to a circle with Centre O is 8 centimetre if the radius of the circle is 6 CM then the length of OP is
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10
Step-by-step explanation:
let PQ be the tangent drawn from the point P
As we know,
radius is always perpendicular to the tangent of a circle
then,
PQ=8cm=base(b)
OQ=radius =6 cm= perpendicular(p)
op=hypoteneous (h)=?
using pythagoras theorem,
h^2= p^2+b^2
therefore, h=OP=10 cm
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