Question

The area of a square is equal to the area of a rectangle of length 8 cm and breadth 2 cm. What is the side of the square?

Answer 1

Step-by-step explanation:

Breadthoftherectangle=2cm

Dimensions of a square:

Side of a square (a)=8 cm

Dimensions of a rectangle:

Length (l)= 32 cm,

Let breadth = b cm

Area of square =sidexside =8x8=64 cm

that is equal to area of rectangle.

area of rectangle=lxb ,where L=32

so b=64/32

the ans is 2 cm

b=2cm

Answer 2

Step-by-step explanation:

$\blue{ \bf{ \underline{Question : }}}$

The area of a square is equal to the area of a rectangle of length 8 cm and breadth 2 cm. What is the side of the square?

$\boxed{ \huge{ \bold{Given}}}$

• Length (l) = 8 cm

• Breadth (b) = 2 cm

$\boxed{ \huge{ \bold{to \: find}}}$

• Side of the Square

$\star{ \pink{ \underline{ \underline{Ｓｏｌｕｔｉｏｎ : - }}}}$

We Know,

$\boxed{ \red{ \sf{Area \: of \: the \: Square = {side}^{2} }}}$

$\boxed{ \red{ \sf{Area \: of \: the \: Rectangle = lenght \times breadth}}}$

$\bold{ \underline {According \: to \: the \: Question,}}$

$\boxed{ \orange{ \underbrace{ \sf{Area \: of \: Square = Area \: of \: Rectangle}}}}$

$\: \: \: \: \: \: \: \: \: {\implies{ \sf{ {side}^{2} = 8 \times 2}}}$

$\: \: \: \: \: \: \: \: \: {\implies{ \sf{ {side}^{2} = 16}}}$

$\: \: \: \: \: \: \: \: \: {\implies{ \sf{ {side}^{} = \sqrt{16} }}}$

$\: \: \: \: \: \: \: \: \: {\implies{ \sf{ {side} = \boxed{ \red{ \frak{ 4 \: cm}}}}}}$

$\therefore{ \sf{ \green{Side \: of \: Square = 4 \: cm}}}$

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